Equation of the given line is:
y = 3x + 2
Slope of the line = m = 3
Since we are to find equation of line parallel to this line, the slope of new line will be the same as slope of parallel lines is the same.
So we are to find a line with slope 3 and passing through the point (10,1). Using the point-slope form of equation we can write:
y - 1 = 3(x - 10)
y = 3x - 30 + 1
y = 3x - 29
⇒
- 3x + y = 29
So option C gives the correct equation of the line.
