briannaml
briannaml
25-04-2018
Mathematics
contestada
PLZ HELP ASAP RIGHT TRIANGLES
Respuesta :
IsrarAwan
IsrarAwan
25-04-2018
The correct answer is: AC = [tex]9 \sqrt{3} [/tex]
Explanation:
Since
[tex]sin(\theta) = perpendicular/hypotenuse [/tex]
Here
[tex]\theta[/tex] = 60°
Perpendicular = x = ?
Hypotenuse = AB = 18
So
Perpendicular = A = sin(60)*18
x = AC = [tex]9 \sqrt{3} [/tex]
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