charityclark9024 charityclark9024
  • 26-04-2018
  • Mathematics
contestada

"how many ways are there to construct a string of 3 digits if numbers cannot be repeated

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musiclover10045
musiclover10045 musiclover10045
  • 26-04-2018
there are 10 total digits ( 0, 1 , 2, 3, 4, 5, 6, 7,8 ,9)

1st digit can be 1 of 10
2nd digit can be 1 of 9 ( 10-1 because a number cannot repeat)
3rd digit can be 1 of 8 ( 9-1 because no number can repeat)

total combinations = 10 * 9 * 8 = 720
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konrad509
konrad509 konrad509
  • 12-08-2018

[tex] \underbrace{10}_{\text{1 of 10 digits}}\cdot \underbrace{9}_{\text{1 of remaining 9 digits}}\cdot \underbrace{8}_{\text{1 of remaining 8 digits}}=720 [/tex]

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